Y=2x2+16x-20

Solution for Y=2x2+16x-20 equation:

=2Y^2+16Y-20

We move all terms to the left:

-(2Y^2+16Y-20)=0

We get rid of parentheses

-2Y^2-16Y+20=0

a = -2; b = -16; c = +20;
Δ = b2-4ac
Δ = -162-4·(-2)·20
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{26}}{2*-2}=\frac{16-4\sqrt{26}}{-4}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{26}}{2*-2}=\frac{16+4\sqrt{26}}{-4}
$