Y=2x2+14x

Solution for Y=2x2+14x equation:

=2Y^2+14Y

We move all terms to the left:

-(2Y^2+14Y)=0

We get rid of parentheses

-2Y^2-14Y=0

a = -2; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·(-2)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*-2}=\frac{0}{-4}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*-2}=\frac{28}{-4}
=-7
$