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-(-5)=(2/9)(Y-8)
We move all terms to the left:
-(-5)-((2/9)(Y-8))=0
Domain of the equation: 9)(Y-8))!=0We add all the numbers together, and all the variables
Y∈R
-((+2/9)(Y-8))-(-5)=0
We add all the numbers together, and all the variables
-((+2/9)(Y-8))+5=0
We multiply parentheses ..
-((+2Y^2+2/9*-8))+5=0
We multiply all the terms by the denominator
-((+2Y^2+2+5*9*-8))=0
We calculate terms in parentheses: -((+2Y^2+2+5*9*-8)), so:a = -2; b = 0; c = 0;
(+2Y^2+2+5*9*-8)
We get rid of parentheses
2Y^2+2-8+5*9*
We add all the numbers together, and all the variables
2Y^2
Back to the equation:
-(2Y^2)
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$Y=\frac{-b}{2a}=\frac{0}{-4}=0$
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