3y+3=1+7(3y-3)

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Solution for 3y+3=1+7(3y-3) equation: 



3y+3=1+7(3y-3)

We move all terms to the left:

3y+3-(1+7(3y-3))=0



We calculate terms in parentheses: -(1+7(3y-3)), so:

1+7(3y-3)

determiningTheFunctionDomain
7(3y-3)+1

We multiply parentheses

21y-21+1

We add all the numbers together, and all the variables

21y-20

Back to the equation:

-(21y-20)



We get rid of parentheses

3y-21y+20+3=0

We add all the numbers together, and all the variables

-18y+23=0

We move all terms containing y to the left, all other terms to the right

-18y=-23

y=-23/-18

y=1+5/18

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