Y+4/5x=27

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Solution for Y+4/5x=27 equation: 



+4/5Y=27

We move all terms to the left:

+4/5Y-(27)=0



Domain of the equation: 5Y!=0

Y!=0/5

Y!=0

Y∈R



We multiply all the terms by the denominator


-27*5Y+4=0

Wy multiply elements

-135Y+4=0

We move all terms containing Y to the left, all other terms to the right

-135Y=-4

Y=-4/-135

Y=4/135

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