7(x+3)=2x+33

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Solution for 7(x+3)=2x+33 equation: 



7(x+3)=2x+33

We move all terms to the left:

7(x+3)-(2x+33)=0

We multiply parentheses

7x-(2x+33)+21=0

We get rid of parentheses

7x-2x-33+21=0

We add all the numbers together, and all the variables

5x-12=0

We move all terms containing x to the left, all other terms to the right

5x=12

x=12/5

x=2+2/5

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