Y+4(2y+1)=8+2y-1

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Solution for Y+4(2y+1)=8+2y-1 equation: 



+4(2Y+1)=8+2Y-1

We move all terms to the left:

+4(2Y+1)-(8+2Y-1)=0

We add all the numbers together, and all the variables

4(2Y+1)-(2Y+7)=0

We multiply parentheses

8Y-(2Y+7)+4=0

We get rid of parentheses

8Y-2Y-7+4=0

We add all the numbers together, and all the variables

6Y-3=0

We move all terms containing Y to the left, all other terms to the right

6Y=3

Y=3/6

Y=1/2

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