0.13x+0.2(x-4)=0.01(4x-1)

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Solution for 0.13x+0.2(x-4)=0.01(4x-1) equation: 



0.13x+0.2(x-4)=0.01(4x-1)

We move all terms to the left:

0.13x+0.2(x-4)-(0.01(4x-1))=0

We multiply parentheses

0.13x+0.2x-(0.01(4x-1))-0.8=0



We calculate terms in parentheses: -(0.01(4x-1)), so:

0.01(4x-1)

We multiply parentheses

0.04x-0.01

Back to the equation:

-(0.04x-0.01)



We add all the numbers together, and all the variables

0.33x-(0.04x-0.01)-0.8=0

We get rid of parentheses

0.33x-0.04x+0.01-0.8=0

We add all the numbers together, and all the variables

0.29x-0.79=0

We move all terms containing x to the left, all other terms to the right

0.29x=0.79

x=0.79/0.29

x=2+0.21/0.29

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