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+1=1/5(Y+10)
We move all terms to the left:
+1-(1/5(Y+10))=0
Domain of the equation: 5(Y+10))!=0We multiply all the terms by the denominator
Y∈R
-(1+1*5(Y+10))=0
We calculate terms in parentheses: -(1+1*5(Y+10)), so:
1+1*5(Y+10)
determiningTheFunctionDomain 1*5(Y+10)+1
Wy multiply elements
5Y(Y+1
Back to the equation:
-(5Y(Y+1)
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| y=5(4)-7 | | 12+2w=39 | | 12=10w−6 | | y-6=(12)+6 | | n/16=37 | | 6x-22=48-x | | -2.2-(-4x-2)=-(-x-3.1) | | 9x2=27x | | 171=(n-2)*180 | | 2x2+2x=5 | | 0.4(2x-3)=2 | | 458n=495-37= | | 4+5*n=39 | | 5(x-6)=120 | | 4x+5=-3x-8 | | 7(w−4)=−2w−37 | | 3.5w=31.5= | | -2x=-2x-2(1.6x+4.8) | | Y=1.50x+7 | | x/26=-10/13 | | 90+(71x-1)+20x=180 | | 19+12x-17x=-1 | | -v+7=14 | | m*3.54=1.5 | | 90+(71-1)+20x=180 | | x+3/2=10/8 | | 2 a + 2 = 24 | | 32+1.8c=33.8 | | 5y-3+18y+3=180 | | 3(2r+2)=2(3+3r) | | 28.8=t+5.1 | | v+5/v+3=v+6+v+4+1 |