3(2r+2)=2(3+3r)

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Solution for 3(2r+2)=2(3+3r) equation: 



3(2r+2)=2(3+3r)

We move all terms to the left:

3(2r+2)-(2(3+3r))=0

We add all the numbers together, and all the variables

3(2r+2)-(2(3r+3))=0

We multiply parentheses

6r-(2(3r+3))+6=0



We calculate terms in parentheses: -(2(3r+3)), so:

2(3r+3)

We multiply parentheses

6r+6

Back to the equation:

-(6r+6)



We get rid of parentheses

6r-6r-6+6=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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