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35=5/9x-32
We move all terms to the left:
35-(5/9x-32)=0
Domain of the equation: 9x-32)!=0We get rid of parentheses
x∈R
-5/9x+32+35=0
We multiply all the terms by the denominator
32*9x+35*9x-5=0
Wy multiply elements
288x+315x-5=0
We add all the numbers together, and all the variables
603x-5=0
We move all terms containing x to the left, all other terms to the right
603x=5
x=5/603
x=5/603
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