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X=5/4X
We move all terms to the left:
X-(5/4X)=0
Domain of the equation: 4X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(+5/4X)=0
We get rid of parentheses
X-5/4X=0
We multiply all the terms by the denominator
X*4X-5=0
Wy multiply elements
4X^2-5=0
a = 4; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·4·(-5)
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{5}}{2*4}=\frac{0-4\sqrt{5}}{8} =-\frac{4\sqrt{5}}{8} =-\frac{\sqrt{5}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{5}}{2*4}=\frac{0+4\sqrt{5}}{8} =\frac{4\sqrt{5}}{8} =\frac{\sqrt{5}}{2} $
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