28=7(x-5)+2x

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Solution for 28=7(x-5)+2x equation: 



28=7(x-5)+2x

We move all terms to the left:

28-(7(x-5)+2x)=0



We calculate terms in parentheses: -(7(x-5)+2x), so:

7(x-5)+2x

We add all the numbers together, and all the variables

2x+7(x-5)

We multiply parentheses

2x+7x-35

We add all the numbers together, and all the variables

9x-35

Back to the equation:

-(9x-35)



We get rid of parentheses

-9x+35+28=0

We add all the numbers together, and all the variables

-9x+63=0

We move all terms containing x to the left, all other terms to the right

-9x=-63

x=-63/-9

x=+7

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