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X=5-2/2X
We move all terms to the left:
X-(5-2/2X)=0
Domain of the equation: 2X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(-2/2X+5)=0
We get rid of parentheses
X+2/2X-5=0
We multiply all the terms by the denominator
X*2X-5*2X+2=0
Wy multiply elements
2X^2-10X+2=0
a = 2; b = -10; c = +2;
Δ = b2-4ac
Δ = -102-4·2·2
Δ = 84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{84}=\sqrt{4*21}=\sqrt{4}*\sqrt{21}=2\sqrt{21}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{21}}{2*2}=\frac{10-2\sqrt{21}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{21}}{2*2}=\frac{10+2\sqrt{21}}{4} $
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