7(1+4n)=7(6+2n)+7n

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Solution for 7(1+4n)=7(6+2n)+7n equation: 



7(1+4n)=7(6+2n)+7n

We move all terms to the left:

7(1+4n)-(7(6+2n)+7n)=0

We add all the numbers together, and all the variables

7(4n+1)-(7(2n+6)+7n)=0

We multiply parentheses

28n-(7(2n+6)+7n)+7=0



We calculate terms in parentheses: -(7(2n+6)+7n), so:

7(2n+6)+7n

We add all the numbers together, and all the variables

7n+7(2n+6)

We multiply parentheses

7n+14n+42

We add all the numbers together, and all the variables

21n+42

Back to the equation:

-(21n+42)



We get rid of parentheses

28n-21n-42+7=0

We add all the numbers together, and all the variables

7n-35=0

We move all terms containing n to the left, all other terms to the right

7n=35

n=35/7

n=5

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