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X=3/6X-1
We move all terms to the left:
X-(3/6X-1)=0
Domain of the equation: 6X-1)!=0We get rid of parentheses
X∈R
X-3/6X+1=0
We multiply all the terms by the denominator
X*6X+1*6X-3=0
Wy multiply elements
6X^2+6X-3=0
a = 6; b = 6; c = -3;
Δ = b2-4ac
Δ = 62-4·6·(-3)
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{3}}{2*6}=\frac{-6-6\sqrt{3}}{12} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{3}}{2*6}=\frac{-6+6\sqrt{3}}{12} $
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