If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(x-5)(x-5)=9
We move all terms to the left:
(x-5)(x-5)-(9)=0
We multiply parentheses ..
(+x^2-5x-5x+25)-9=0
We get rid of parentheses
x^2-5x-5x+25-9=0
We add all the numbers together, and all the variables
x^2-10x+16=0
a = 1; b = -10; c = +16;
Δ = b2-4ac
Δ = -102-4·1·16
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-6}{2*1}=\frac{4}{2} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+6}{2*1}=\frac{16}{2} =8 $
| 4(3x+5)=7x+75 | | 5t-17=t+27 | | 9y+6=4y+21 | | 2x×3=x+5 | | 3=w/2+3 | | 96=-3x+6 | | 7(5x-2)=10 | | 4(2r+2)=40 | | 7-h=46 | | x+3(5x)=2000 | | 6+2a=20 | | 4t+11=31 | | 130=20x+50 | | 4x+3+2x–8=25 | | 2.51t=6.17t-4.62 | | 4b+4=10 | | 79=8p+7 | | 45-3/5p=102 | | 12+b=-3b+32 | | 4w+7=19 | | 7|12x+3|-1=62 | | 2(-x-2)^2=10 | | -9+2k=k-2k | | (x+3)^2-9=-5 | | -5(3x+4)=2(-6x+4)+11x | | 16(c+4)^2-1=0 | | 9-4n=-10n-15 | | 16x^2=2+4x | | 4/x-2=12/2x-1 | | 0=x(20-2x)(12-2x) | | 45=9x^2 | | x=x(20-2x)(12-2x) |