X2-60x+800=800

Solution for X2-60x+800=800 equation:

X2-60X+800=800

We move all terms to the left:

X2-60X+800-(800)=0

We add all the numbers together, and all the variables

X^2-60X=0

a = 1; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·1·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*1}=\frac{0}{2}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*1}=\frac{120}{2}
=60
$