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((6x+3)/5)=3x+9
We move all terms to the left:
((6x+3)/5)-(3x+9)=0
We get rid of parentheses
((6x+3)/5)-3x-9=0
We multiply all the terms by the denominator
((6x+3)-3x*5)-9*5)=0
We calculate terms in parentheses: +((6x+3)-3x*5), so:We add all the numbers together, and all the variables
(6x+3)-3x*5
Wy multiply elements
(6x+3)-15x
We get rid of parentheses
6x-15x+3
We add all the numbers together, and all the variables
-9x+3
Back to the equation:
+(-9x+3)
(-9x+3)=0
We get rid of parentheses
-9x+3=0
We move all terms containing x to the left, all other terms to the right
-9x=-3
x=-3/-9
x=1/3
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