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X2-45X+350=0
We add all the numbers together, and all the variables
X^2-45X+350=0
a = 1; b = -45; c = +350;
Δ = b2-4ac
Δ = -452-4·1·350
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-25}{2*1}=\frac{20}{2} =10 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+25}{2*1}=\frac{70}{2} =35 $
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