9+3b+2(b+1)=67

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Solution for 9+3b+2(b+1)=67 equation: 



9+3b+2(b+1)=67

We move all terms to the left:

9+3b+2(b+1)-(67)=0

We add all the numbers together, and all the variables

3b+2(b+1)-58=0

We multiply parentheses

3b+2b+2-58=0

We add all the numbers together, and all the variables

5b-56=0

We move all terms containing b to the left, all other terms to the right

5b=56

b=56/5

b=11+1/5

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