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X2-3500X+31500=0
We add all the numbers together, and all the variables
X^2-3500X+31500=0
a = 1; b = -3500; c = +31500;
Δ = b2-4ac
Δ = -35002-4·1·31500
Δ = 12124000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12124000}=\sqrt{400*30310}=\sqrt{400}*\sqrt{30310}=20\sqrt{30310}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3500)-20\sqrt{30310}}{2*1}=\frac{3500-20\sqrt{30310}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3500)+20\sqrt{30310}}{2*1}=\frac{3500+20\sqrt{30310}}{2} $
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