(11+3x)+(19+x)=(5x+2)

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Solution for (11+3x)+(19+x)=(5x+2) equation: 



(11+3x)+(19+x)=(5x+2)

We move all terms to the left:

(11+3x)+(19+x)-((5x+2))=0

We add all the numbers together, and all the variables

(3x+11)+(x+19)-((5x+2))=0

We get rid of parentheses

3x+x-((5x+2))+11+19=0



We calculate terms in parentheses: -((5x+2)), so:

(5x+2)

We get rid of parentheses

5x+2

Back to the equation:

-(5x+2)



We add all the numbers together, and all the variables

4x-(5x+2)+30=0

We get rid of parentheses

4x-5x-2+30=0

We add all the numbers together, and all the variables

-1x+28=0

We move all terms containing x to the left, all other terms to the right

-x=-28

x=-28/-1

x=+28

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