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X2-15X+40=0
We add all the numbers together, and all the variables
X^2-15X+40=0
a = 1; b = -15; c = +40;
Δ = b2-4ac
Δ = -152-4·1·40
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{65}}{2*1}=\frac{15-\sqrt{65}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{65}}{2*1}=\frac{15+\sqrt{65}}{2} $
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