X2+8x-2400=0

Solution for X2+8x-2400=0 equation:

X2+8X-2400=0

We add all the numbers together, and all the variables

X^2+8X-2400=0

a = 1; b = 8; c = -2400;
Δ = b2-4ac
Δ = 82-4·1·(-2400)
Δ = 9664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9664}=\sqrt{64*151}=\sqrt{64}*\sqrt{151}=8\sqrt{151}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{151}}{2*1}=\frac{-8-8\sqrt{151}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{151}}{2*1}=\frac{-8+8\sqrt{151}}{2}
$