9j-2=1/3(6-27j)

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Solution for 9j-2=1/3(6-27j) equation: 



9j-2=1/3(6-27j)

We move all terms to the left:

9j-2-(1/3(6-27j))=0



Domain of the equation: 3(6-27j))!=0

j∈R



We add all the numbers together, and all the variables

9j-(1/3(-27j+6))-2=0

We multiply all the terms by the denominator


9j*3(-27j+6))-(1-2*3(-27j+6))=0

Wy multiply elements

27j^2(--6j(-=0

We use the square of the difference formula

27j^2(+6j(-=0

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