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X2+6.6X+3.3=0
We add all the numbers together, and all the variables
X^2+6.6X+3.3=0
a = 1; b = 6.6; c = +3.3;
Δ = b2-4ac
Δ = 6.62-4·1·3.3
Δ = 30.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.6)-\sqrt{30.36}}{2*1}=\frac{-6.6-\sqrt{30.36}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.6)+\sqrt{30.36}}{2*1}=\frac{-6.6+\sqrt{30.36}}{2} $
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