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x2+12x=-40
We move all terms to the left:
x2+12x-(-40)=0
We add all the numbers together, and all the variables
x^2+12x+40=0
a = 1; b = 12; c = +40;
Δ = b2-4ac
Δ = 122-4·1·40
Δ = -16
Delta is less than zero, so there is no solution for the equation
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