X2+54x=504

Solution for X2+54x=504 equation:

X2+54X=504

We move all terms to the left:

X2+54X-(504)=0

We add all the numbers together, and all the variables

X^2+54X-504=0

a = 1; b = 54; c = -504;
Δ = b2-4ac
Δ = 542-4·1·(-504)
Δ = 4932
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4932}=\sqrt{36*137}=\sqrt{36}*\sqrt{137}=6\sqrt{137}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-6\sqrt{137}}{2*1}=\frac{-54-6\sqrt{137}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+6\sqrt{137}}{2*1}=\frac{-54+6\sqrt{137}}{2}
$