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X2+3X-2.5=0
We add all the numbers together, and all the variables
X^2+3X-2.5=0
a = 1; b = 3; c = -2.5;
Δ = b2-4ac
Δ = 32-4·1·(-2.5)
Δ = 19
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{19}}{2*1}=\frac{-3-\sqrt{19}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{19}}{2*1}=\frac{-3+\sqrt{19}}{2} $
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