4(3-y)=2(y+3)

Solution for 4(3-y)=2(y+3) equation:

4(3-y)=2(y+3)

We move all terms to the left:

4(3-y)-(2(y+3))=0

We add all the numbers together, and all the variables

4(-1y+3)-(2(y+3))=0

We multiply parentheses

-4y-(2(y+3))+12=0


We calculate terms in parentheses: -(2(y+3)), so:

2(y+3)

We multiply parentheses

2y+6

Back to the equation:

-(2y+6)


We get rid of parentheses

-4y-2y-6+12=0

We add all the numbers together, and all the variables

-6y+6=0

We move all terms containing y to the left, all other terms to the right

-6y=-6

y=-6/-6

y=1