X2+3x+1=4x+3

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Solution for X2+3x+1=4x+3 equation:



X2+3X+1=4X+3
We move all terms to the left:
X2+3X+1-(4X+3)=0
We add all the numbers together, and all the variables
X^2+3X-(4X+3)+1=0
We get rid of parentheses
X^2+3X-4X-3+1=0
We add all the numbers together, and all the variables
X^2-1X-2=0
a = 1; b = -1; c = -2;
Δ = b2-4ac
Δ = -12-4·1·(-2)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-3}{2*1}=\frac{-2}{2} =-1 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+3}{2*1}=\frac{4}{2} =2 $

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