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8(2y+6)5y=37
We move all terms to the left:
8(2y+6)5y-(37)=0
We multiply parentheses
80y^2+240y-37=0
a = 80; b = 240; c = -37;
Δ = b2-4ac
Δ = 2402-4·80·(-37)
Δ = 69440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{69440}=\sqrt{64*1085}=\sqrt{64}*\sqrt{1085}=8\sqrt{1085}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-8\sqrt{1085}}{2*80}=\frac{-240-8\sqrt{1085}}{160} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+8\sqrt{1085}}{2*80}=\frac{-240+8\sqrt{1085}}{160} $
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