1/3(y+6)=1/4(y+5)

Solution for 1/3(y+6)=1/4(y+5) equation:

1/3(y+6)=1/4(y+5)

We move all terms to the left:

1/3(y+6)-(1/4(y+5))=0


Domain of the equation: 3(y+6)!=0

y∈R



Domain of the equation: 4(y+5))!=0

y∈R


We calculate fractions


(4yy/(3(y+6)*4(y+5)))+(-3yy/(3(y+6)*4(y+5)))=0


We calculate terms in parentheses: +(4yy/(3(y+6)*4(y+5))), so:

4yy/(3(y+6)*4(y+5))

We multiply all the terms by the denominator


4yy

Back to the equation:

+(4yy)



We calculate terms in parentheses: +(-3yy/(3(y+6)*4(y+5))), so:

-3yy/(3(y+6)*4(y+5))

We multiply all the terms by the denominator


-3yy

Back to the equation:

+(-3yy)


We get rid of parentheses

4yy-3yy=0