X2+3+x=98

Solution for X2+3+x=98 equation:

X2+3+X=98

We move all terms to the left:

X2+3+X-(98)=0

We add all the numbers together, and all the variables

X^2+X-95=0

a = 1; b = 1; c = -95;
Δ = b2-4ac
Δ = 12-4·1·(-95)
Δ = 381
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{381}}{2*1}=\frac{-1-\sqrt{381}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{381}}{2*1}=\frac{-1+\sqrt{381}}{2}
$