3(2x-5)-6(x+3)=18-2(x+7)-3x

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Solution for 3(2x-5)-6(x+3)=18-2(x+7)-3x equation: 



3(2x-5)-6(x+3)=18-2(x+7)-3x

We move all terms to the left:

3(2x-5)-6(x+3)-(18-2(x+7)-3x)=0

We multiply parentheses

6x-6x-(18-2(x+7)-3x)-15-18=0



We calculate terms in parentheses: -(18-2(x+7)-3x), so:

18-2(x+7)-3x

determiningTheFunctionDomain
-2(x+7)-3x+18

We add all the numbers together, and all the variables

-3x-2(x+7)+18

We multiply parentheses

-3x-2x-14+18

We add all the numbers together, and all the variables

-5x+4

Back to the equation:

-(-5x+4)



We add all the numbers together, and all the variables

-(-5x+4)-33=0

We get rid of parentheses

5x-4-33=0

We add all the numbers together, and all the variables

5x-37=0

We move all terms containing x to the left, all other terms to the right

5x=37

x=37/5

x=7+2/5

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