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X2+2X=9X-6
We move all terms to the left:
X2+2X-(9X-6)=0
We add all the numbers together, and all the variables
X^2+2X-(9X-6)=0
We get rid of parentheses
X^2+2X-9X+6=0
We add all the numbers together, and all the variables
X^2-7X+6=0
a = 1; b = -7; c = +6;
Δ = b2-4ac
Δ = -72-4·1·6
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-5}{2*1}=\frac{2}{2} =1 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+5}{2*1}=\frac{12}{2} =6 $
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