-8x+8=-4/7x+4

Solution for -8x+8=-4/7x+4 equation:

-8x+8=-4/7x+4

We move all terms to the left:

-8x+8-(-4/7x+4)=0


Domain of the equation: 7x+4)!=0

x∈R


We get rid of parentheses

-8x+4/7x-4+8=0

We multiply all the terms by the denominator


-8x*7x-4*7x+8*7x+4=0

Wy multiply elements

-56x^2-28x+56x+4=0

We add all the numbers together, and all the variables

-56x^2+28x+4=0

a = -56; b = 28; c = +4;
Δ = b2-4ac
Δ = 282-4·(-56)·4
Δ = 1680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1680}=\sqrt{16*105}=\sqrt{16}*\sqrt{105}=4\sqrt{105}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4\sqrt{105}}{2*-56}=\frac{-28-4\sqrt{105}}{-112}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4\sqrt{105}}{2*-56}=\frac{-28+4\sqrt{105}}{-112}
$