X2+2x2+10x=20

Solution for X2+2x2+10x=20 equation:

X2+2X^2+10X=20

We move all terms to the left:

X2+2X^2+10X-(20)=0

We add all the numbers together, and all the variables

3X^2+10X-20=0

a = 3; b = 10; c = -20;
Δ = b2-4ac
Δ = 102-4·3·(-20)
Δ = 340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{340}=\sqrt{4*85}=\sqrt{4}*\sqrt{85}=2\sqrt{85}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{85}}{2*3}=\frac{-10-2\sqrt{85}}{6}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{85}}{2*3}=\frac{-10+2\sqrt{85}}{6}
$