X2+24x+135=0

Solution for X2+24x+135=0 equation:

X2+24X+135=0

We add all the numbers together, and all the variables

X^2+24X+135=0

a = 1; b = 24; c = +135;
Δ = b2-4ac
Δ = 242-4·1·135
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-6}{2*1}=\frac{-30}{2}
=-15
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+6}{2*1}=\frac{-18}{2}
=-9
$