8(x+)-3(x-4)=6(x-7)+8

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Solution for 8(x+)-3(x-4)=6(x-7)+8 equation: 



8(x+)-3(x-4)=6(x-7)+8

We move all terms to the left:

8(x+)-3(x-4)-(6(x-7)+8)=0

We add all the numbers together, and all the variables

8(+x)-3(x-4)-(6(x-7)+8)=0

We multiply parentheses

8x-3x-(6(x-7)+8)+12=0



We calculate terms in parentheses: -(6(x-7)+8), so:

6(x-7)+8

We multiply parentheses

6x-42+8

We add all the numbers together, and all the variables

6x-34

Back to the equation:

-(6x-34)



We add all the numbers together, and all the variables

5x-(6x-34)+12=0

We get rid of parentheses

5x-6x+34+12=0

We add all the numbers together, and all the variables

-1x+46=0

We move all terms containing x to the left, all other terms to the right

-x=-46

x=-46/-1

x=+46

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