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X2+241X-9972=0
We add all the numbers together, and all the variables
X^2+241X-9972=0
a = 1; b = 241; c = -9972;
Δ = b2-4ac
Δ = 2412-4·1·(-9972)
Δ = 97969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{97969}=313$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(241)-313}{2*1}=\frac{-554}{2} =-277 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(241)+313}{2*1}=\frac{72}{2} =36 $
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