8y-2(6-2y)=7y-(3y-8)2

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Solution for 8y-2(6-2y)=7y-(3y-8)2 equation: 



8y-2(6-2y)=7y-(3y-8)2

We move all terms to the left:

8y-2(6-2y)-(7y-(3y-8)2)=0

We add all the numbers together, and all the variables

8y-2(-2y+6)-(7y-(3y-8)2)=0

We multiply parentheses

8y+4y-(7y-(3y-8)2)-12=0



We calculate terms in parentheses: -(7y-(3y-8)2), so:

7y-(3y-8)2

We multiply parentheses

7y-6y+16

We add all the numbers together, and all the variables

y+16

Back to the equation:

-(y+16)



We add all the numbers together, and all the variables

12y-(y+16)-12=0

We get rid of parentheses

12y-y-16-12=0

We add all the numbers together, and all the variables

11y-28=0

We move all terms containing y to the left, all other terms to the right

11y=28

y=28/11

y=2+6/11

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