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X2+200X-1600=0
We add all the numbers together, and all the variables
X^2+200X-1600=0
a = 1; b = 200; c = -1600;
Δ = b2-4ac
Δ = 2002-4·1·(-1600)
Δ = 46400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{46400}=\sqrt{1600*29}=\sqrt{1600}*\sqrt{29}=40\sqrt{29}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-40\sqrt{29}}{2*1}=\frac{-200-40\sqrt{29}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+40\sqrt{29}}{2*1}=\frac{-200+40\sqrt{29}}{2} $
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