3x2-24x-1560=0

Solution for 3x2-24x-1560=0 equation:

3x^2-24x-1560=0

a = 3; b = -24; c = -1560;
Δ = b2-4ac
Δ = -242-4·3·(-1560)
Δ = 19296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19296}=\sqrt{144*134}=\sqrt{144}*\sqrt{134}=12\sqrt{134}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12\sqrt{134}}{2*3}=\frac{24-12\sqrt{134}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12\sqrt{134}}{2*3}=\frac{24+12\sqrt{134}}{6}
$