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X2+1=-X-5
We move all terms to the left:
X2+1-(-X-5)=0
We add all the numbers together, and all the variables
X2-(-1X-5)+1=0
We add all the numbers together, and all the variables
X^2-(-1X-5)+1=0
We get rid of parentheses
X^2+1X+5+1=0
We add all the numbers together, and all the variables
X^2+X+6=0
a = 1; b = 1; c = +6;
Δ = b2-4ac
Δ = 12-4·1·6
Δ = -23
Delta is less than zero, so there is no solution for the equation
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