X2+14x=120

Solution for X2+14x=120 equation:

X2+14X=120

We move all terms to the left:

X2+14X-(120)=0

We add all the numbers together, and all the variables

X^2+14X-120=0

a = 1; b = 14; c = -120;
Δ = b2-4ac
Δ = 142-4·1·(-120)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*1}=\frac{-40}{2}
=-20
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*1}=\frac{12}{2}
=6
$