Y(2y+1)(y-4)=0

Solution for Y(2y+1)(y-4)=0 equation:

(2Y+1)(Y-4)=0

We multiply parentheses ..

(+2Y^2-8Y+Y-4)=0

We get rid of parentheses

2Y^2-8Y+Y-4=0

We add all the numbers together, and all the variables

2Y^2-7Y-4=0

a = 2; b = -7; c = -4;
Δ = b2-4ac
Δ = -72-4·2·(-4)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-9}{2*2}=\frac{-2}{4}
=-1/2
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+9}{2*2}=\frac{16}{4}
=4
$