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X2+11X=180
We move all terms to the left:
X2+11X-(180)=0
We add all the numbers together, and all the variables
X^2+11X-180=0
a = 1; b = 11; c = -180;
Δ = b2-4ac
Δ = 112-4·1·(-180)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-29}{2*1}=\frac{-40}{2} =-20 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+29}{2*1}=\frac{18}{2} =9 $
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