(7x+4)5=(3x-2)/4

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Solution for (7x+4)5=(3x-2)/4 equation: 



(7x+4)5=(3x-2)/4

We move all terms to the left:

(7x+4)5-((3x-2)/4)=0

We multiply parentheses

35x-((3x-2)/4)+20=0

We multiply all the terms by the denominator


35x*4)-((3x-2)+20*4)=0

We add all the numbers together, and all the variables

35x*4)-((3x-2)=0

Wy multiply elements

140x^2=0

a = 140; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·140·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{280}=0$

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